Dear all,
My question is illustrated by the following example:
I have a matrix M:
> M<-
> matrix(c("0","0","1","1","0","1","1","0","0","*","1","1","0","1","*"),nrow=3)
> colnames(M)<- c("2006","2007","2008","2009","2010")
> M
2006 2007 2008 2009 2010
[1,] "0" "1" "1" "*" "0"
[2,] "0" "0" "0" "1" "1"
[3,] "1" "1" "0" "1" "*"
> pattern<- c("0","1")
I would like to find, for each row, if it contains exactly the pattern of two
character strings, beginning with a "0" and followed by a "1", i.e, exactly "0"
"1". If it does, at which year?
E.g. It should return 2006 for row 1, 2008 for row 2 and 2008 for row 3.
For as far as I know, the variations of the grep function group cannot search
for a pattern that has 2 or more character strings. I could do it with a loop
but I seek a more efficient way than a loop. How should I do it? Really
appreciated for your help!!!
Best regards,
Jing Liu
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
