On 2/11/08, willem vervoort <[EMAIL PROTECTED]> wrote:
> Dear R-help list,
>
> I am trying to construct a lattice histogram using 3 factors.
>
> My dataframe looks like this: (simulating a waterbalance over
> groundwater with different salinities)
>
> s days model EC EC_max
> 0.4 1 "A" 10 9
> 0.42 2 "A" 10 9
> 0.44 3 "A" 10 9
> : : : : :
> 0.4 1 "B" 10 9
> : : : : :
> 0.4 1 "A" 30 9
> : : : : :
> 0.4 1 "A" 30 36
>
> Anyway you get the gist
> EC_max has two levels 9 and 36, EC has 3 levels 10, 30 and 70, and
> model has two levels ("A" and "B"). There are say 365 days and s is
> the variable of interest (soil saturation)
>
> Can maybe be reproduced with:
> data <- data.frame(s = rnorm(2*3*365*2),rep(1:365,12), model =
> sort(rep(c("A","B"),6*365)),
> EC = rep(sort(rep(c(10,30,70),365*2)),2), EC_max =
> rep(sort(rep(c(9,36),3*365)),2))
>
> I would like to plot histograms with the three factors using Lattice
> so I had the following code:
>
> my.strip <- function(which.given, ..., factor.levels) {
> levs <- if (which.given == 1) c("Model A","Model B")
> else {if(which.given == 2) paste("EC =
> ",as.character(EC),"dS/m")
> else paste("ECmax = ",as.character(EC_max),"dS/m")}
> strip.default(which.given, ..., factor.levels = levs)
> }
>
> histogram(~s|model*as.factor(EC)*as.factor(EC_max),data=Store,xlab="soil
> saturation",type="density",strip=my.strip)
>
> But I am doing something wrong, because it plots the histogram for
> factor level EC_max =9 first and than straight over it the histogram
> for factor level 36, so only 6 panels on the graph rather than 12.
>
> I searched the archives, but no luck so far.
Look up the 'layout' argument in ?xyplot. By default, for 2 or more
conditioning variables, the levels of the first two define columns and
rows, and the rest are spread out over multiple pages. In your
example, you could try layout = c(6, 2) for starters.
-Deepayan
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