Hi r-help-boun...@r-project.org napsal dne 23.12.2010 05:13:37:
> Dear friends, hope I could be able to explain my problem through following > example. Please consider this: > > > > > set.seed(1) > > > input <- rnorm(10) > > > input > > [1] -0.6264538 0.1836433 -0.8356286 1.5952808 0.3295078 -0.8204684 > 0.4874291 0.7383247 0.5757814 -0.3053884 > > > tag <- vector(length=10) > > > > for(i in 1:10) > > # if there is any ****error**** in evaluating "log(input[i])" (or > evaluating some function) then tag[i] = 1, otherwise tag[i] = 0 > > > > Therefore my "tag" vector should like: tag[1]=1, tag[2]=0, tag[3]=1, > tag[4]=0, tag[5]=0....... > > > > Actually R returns logarithm of a negative number as NaN, however in this > example please consider R returns error when it encounters logarithm of a > negative number. > I do not understand above sentence well. R returns NaN not error. For error handling in loop use try or tryCatch. For simple vectorised function evaluation as log you can use is.* evaluation is.nan(log(input))*1 [1] 1 0 1 0 0 1 0 0 0 1 ifelse(is.nan(log(input)), 1,0) [1] 1 0 1 0 0 1 0 0 0 1 Regards Petr > > > Is there any way to do above task? > > > > Thanks and regards, > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.