Dear R helpers!
Let me first wish all of you "Merry Christmas and Very Happy New year 2011"
"Christmas day is a day of Joy and Charity,
May God make you rich in both" - Phillips Brooks
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I have a process which generates number of outputs. The R code for the same is
as given below.
for(i in 1:n)
{
write.csv(output[i], file = paste("output", i, ".csv", sep = ""), row.names =
FALSE)
}
Depending on value of 'n', I get different output files.
Suppose n = 3, that means I am having three output csv files viz.
'output1.csv', 'output2.csv' and 'output3.csv'
output1.csv
date yield_rate
12/23/2010 5.25
12/22/2010 5.19
.................................
.................................
output2.csv
date yield_rate
12/23/2010 4.16
12/22/2010 4.59
.................................
.................................
output3.csv
date yield_rate
12/23/2010 6.15
12/22/2010 6.41
.................................
.................................
Thus all the output files have same column names viz. Date and yield_rate.
Also, I do need these files individually too.
My further requirement is to have a single dataframe as given below.
Date yield_rate1 yield_rate2
yield_rate3
12/23/2010 5.25 4.16
6.15
12/22/2010 5.19 4.59
6.41
...............................................................................................
...............................................................................................
where yield_rate1 = output1$yield_rate and so on.
One way is to simply create a dataframe as
df = data.frame(Date = read.csv('output1.csv')$Date, yield_rate1 =
read.csv('output1.csv')$yield_rate, yield_rate2 =
read.csv('output2.csv')$yield_rate,
yield_rate3 = read.csv('output3.csv')$yield_rate)
However, the problem arises when I am not aware how many output files are there
as n can be 5 or even 100.
So is it possible to write some loop or some function which will enable me to
read 'n' files individually and then keeping "Date" common, only pickup the
yield_curve data from each output file.
Thanking in advance for any guidance.
Regards
Amy
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