It looks like you might be asking for this. This gets the "lower right"
diagonal.
> mat <- matrix(c(1,4,3,4,1,2,3,2,1), nrow = 3, ncol=3, byrow=TRUE)
> mat
[,1] [,2] [,3]
[1,] 1 4 3
[2,] 4 1 2
[3,] 3 2 1
> diag(mat[rev(2:nrow(mat)),-1])
[1] 2 2
>
This gets the upper off-diagonal
> diag(mat[,-1])
[1] 4 2
Rich
You can accomplish much with subscripting.
Rich
On Thu, Jan 20, 2011 at 4:20 PM, Joe P King <j...@joepking.com> wrote:
> So many matrices are square symmetrical (i.e. variance-covariance
> matrices),
> is there any way to get R to split the matrix on its diagonal and just
> return one diagonal?
>
>
>
> So if I have
>
>
>
> mat<-matrix(c(1,4,3,4,1,2,3,2,1), nrow = 3, ncol=3, byrow=TRUE)
>
>
>
> is there anyway to get the lower right diagonal instead of the entire
> symmetric matrix?
>
>
>
> -------------------------------------------
>
> Joe King, M.A.
>
> Ph.D. Student
>
> University of Washington - Seattle
>
> 206-913-2912
>
> <mailto:j...@joepking.com> j...@joepking.com
>
> -------------------------------------------
>
> Ad astra per aspera - "Through hardships to the stars"
>
>
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide
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>
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