I sent this to Siri Bjoner so I dont know if that is allowed or even if it went through.
Simulate 1000 observations from the student-t distribution with 3 > degrees of freedom and then calculate the truncated mean by > excluding bottom 5% and top 5%. This is the question I had and I posted it as soon as I started working on it myself. so this is what I have and now I am asking if this is right or wrong, I am not asking for you to solve this for me without me doing any work. # We first simulate 1000 observations ..... x<-rt(1000,3) mean(x,trim=0.05) #or 0.1 I am not sure z<-sort(x) #next use either y<-z[-c(1:50,951:1000)] # We want the bottom 5% and top 5% so this corresponds to the elements that we are taking away. #or #y<-z[-c(1:100,901:1000)] mean(y) Thank you and I hope you understand now [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.