Try this:

 gsub(".*\\((\\d+)\\).*", "\\1", aaa)

On Tue, Feb 1, 2011 at 3:42 PM, Yan Jiao <y.j...@ucl.ac.uk> wrote:

> Dear R guru:
>
>
>
> If I got a variable
>
> aaa<- "up.6.11(16)"
>
>
>
> how can I extract 16 out of the bracket?
>
> I could use substr, e.g.
>
> substr(aaa, start=1, stop=2)
>
> [1] "up"
>
>
>
> But it needs start and stop, what if my start or stop is not fixed, I
> just want the number inside the bracket, how can I achieve this?
>
>
>
> Many thanks
>
>
>
> yan
>
>
> **********************************************************************
> This email and any files transmitted with it are confide...{{dropped:10}}
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

        [[alternative HTML version deleted]]

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to