On Feb 4, 2011, at 1:41 PM, DB1984 wrote:


Thanks David - but '1' (if I understood correctly) returns the same value for
each row, which I took to be an error.

And exactly what were you expecting with that data?


nt
    V1    V2    V3    V4    V5    V6
1 24.71 23.56 24.71 23.56 24.71 23.56
2 25.64 25.06 25.64 25.06 25.64 25.06
3 21.29 20.87 21.29 20.87 21.29 20.87
4 25.92 26.92 25.92 26.92 25.92 26.92
5 24.36 23.60 24.36 23.60 24.36 23.60
6 24.91 24.32 24.91 24.32 24.91 24.32
7 23.56 23.14 23.56 23.14 23.56 23.14
8 23.94 23.99 23.94 23.99 23.94 23.99
9 26.65 26.07 26.65 26.07 26.65 26.07

test <- apply(nt, 1, shapiro.test)

Run this and ponder the results a bit:

 apply(nt, 1, diff )

--

David.

fred<-data.frame(sapply(test,function(x)c(x$statistic, x$p.value)))
fred
X1 X2 X3 X4 X5 X6
X7          X8          X9
W 0.682676792 0.682676792 0.682676792 0.682676792 0.682676882 0.682676792
0.682676792 0.682676792 0.682676792
0.004039347 0.004039347 0.004039347 0.004039347 0.004039358 0.004039347
0.004039347 0.004039347 0.004039347


Version details are below:
R.Version()
$platform
[1] "x86_64-apple-darwin9.8.0"

$arch
[1] "x86_64"

$os
[1] "darwin9.8.0"

$system
[1] "x86_64, darwin9.8.0"

$status
[1] ""

$major
[1] "2"

$minor
[1] "12.0"

$year
[1] "2010"

$month
[1] "10"

$day
[1] "15"

$`svn rev`
[1] "53317"

$language
[1] "R"

$version.string
[1] "R version 2.12.0 (2010-10-15)"
--
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David Winsemius, MD
West Hartford, CT

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