On Thu, Feb 17, 2011 at 3:39 PM, Stephen Sefick <ssef...@gmail.com> wrote: > Janet: > > The zoo package and aggregate.zoo should do the trick. I have done this > many times with these tools.
Here is some code. Suppose precip is the data. We convert it to a zoo object with date/times assuming the first one is at the start of 2000-01-01. Then we aggregate them by day: > library(zoo) > library(chron) > precip <- 1:200 # sample data > z <- zooreg(precip, start = as.chron("2000-01-01 00:00:00"), freq = 96) > z.ag <- aggregate(z, as.Date) > z.ag 2000-01-01 2000-01-02 2000-01-03 4656 13872 1572 -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.