Peter,
as the matrices in the list have the same shape, you can unlist them
into an array and then use rowMeans.
HTH
Claudia
Am 15.03.2011 21:17, schrieb hihi:
Hi All,
is there any effiective and dense/compact method to calculate the mean of a
list of - of course coincident - matrices on an element by element basis? The
resulting matrix' [i, j]-th element is the mean of the list's matrices' [i,
j]-th elements respectively...
Iterating by for statement is quite straightforward, but I am seeking for a
more elegant solution, and my attempt with the apply family of functions did
not work.
Thank you,
by
Peter
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.