Dear R users, I want to do a fitted.contour plot of selected columns of a dataframe M with M$AM and M$Irradiance as x and y axes respectively. The level of the contour shall be determined by M$PR.
Some words on my data first. Dataframe M looks like: head(M$Irradiance) [1] 293 350 412 419 477 509 head(M$AM) [1] 2.407 2.161 1.964 1.805 1.673 1.563 head(M$PR) [1] 70.102 72.600 75.097 80.167 79.644 82.633 To create a grid, I used "interp" from the "akima" package up until now. As mentioned in the header, I run into problems when trying the following: grid <- akima::interp(M$AM,M$Irradiance,M$PR, duplicate="mean"); Error in interp.old(x, y, z, xo = xo, yo = yo, ncp = 0, extrap = extrap, : scales of x and y are too dissimilar M$Irradiance constists mostly of 3 digit integers, whereas M$AM of decimal numbers. Now, is there another function like interp that can handle this? I could not find a clue in the doc. Should I look deeper into the doc? Maybe transform the y axis? Additionally, I was told in a previous post to include a working example. I do not know how to do that properly. Shall I post code to reproduce a similar data frame or even attach my csv file? Best Regards, Michael Bach [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.