Hi Anna, On Sun, Mar 20, 2011 at 2:54 PM, Anna Lee <ana-...@web.de> wrote: > Hey List, > > I did a multiple regression and my final model looks as follows: > > model9<-lm(calP ~ nsP + I(st^2) + distPr + I(distPr^2)) > > Now I tried to predict the values for calP from this model using the > following function: > > xv<-seq(0,89,by=1) > yv<-predict(model9,list(distPr=xv,st=xv,nsP=xv))
The second argument to predict.lm is newdata, which should be a data.frame. see ?predict.lm. Beyond that though, I'm not sure what you are trying to accomplish. The way you've set this up you would get predicted values for cases like distPr st nsp 0 0 0 1 1 1 2 2 2 . . . 89 89 89 Is that really what you want? Best, Ista > > The predicted values are however strange. Now I do not know weather > just the model does not fit the data (actually all coefficiets are > significant and the plot(model) shows a good shape) or wether I did > something wrong with my prediction command. Does anyone have an > idea??? > > -- > > > Thanks a lot, Anna > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Ista Zahn Graduate student University of Rochester Department of Clinical and Social Psychology http://yourpsyche.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
