On 29/04/2011 9:34 PM, Miao wrote:
Thanks Duncan for clarifying this.  I'm pretty a newbie to such type of
characters and special characters.  In R's gsub() what regular
expressions shall I use to handle all these situations?

I don't know.  This might work:

gsub("[\x01-\x1f\x7f-\xff]", "", x)

(i.e. the range from character 1 to character 31, and 127 to 255) but I don't know if our regular expression matcher will accept those characters.

Duncan Murdoch



On Fri, Apr 29, 2011 at 6:07 PM, Duncan Murdoch
<murdoch.dun...@gmail.com <mailto:murdoch.dun...@gmail.com>> wrote:

    On 29/04/2011 7:41 PM, Miao wrote:

        Hello,

        Can anyone help on gsub() in R?  I have a string like something
        below, and
        wanted to delete all the strings with leading backslash,
        including "\xa0On",
        "\023, "\xab", and many others.   How should I write a regular
        expression
        pattern in gsub()?  I don't care how many characters following
        backslash.



    If those are R strings, none of them contain a backslash.  In R, a
    backslash would always be printed as \\.

    \x is the introduction to a hexadecimal encoding for a character;
    the next two characters show the hex digits.  So your first string
    contains a single character \xa0, the third one contains \xab, and
    so on.

    The \023 is an octal encoding for a single character.

    Duncan Murdoch



        txt<- "Is This Thing\xa0On? http://bit.ly/jAbKem  wait \023 for
        people \xab
        and be patient :"

        Thanks in advance,
        Miao

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