Hi Rui, Here is one option:
ds <- vector("list", 6) for(i in 1:6) ds[[i]] <- list(df = mtcars[, c(i, i + 2)], df2 = mtcars[, c(i, i + 2)] + 10) another could be: altds <- lapply(1:6, function(x) { list(df = mtcars[, c(x, x + 2)], df2 = mtcars[, c(x, x + 2)] + 10) }) all.equal(ds, altds) For some documentation, see ?vector ?lapply Cheers, Josh On Sat, May 21, 2011 at 10:47 AM, Rui Maximo <ruimax...@hotmail.com> wrote: > > Hello, > > I am newbie to R and I want to do this: > > for(i in 1:6) > { > ds[i] <- list(df=data.frame(oilDF[,1],oilDF[,i+2]), > df2=data.frame(oilDF2[,1],oilDF2[,i+2])) > } > > #oilDF and oilDF2 are 2 data frames with several columns. They have different > number of rows > > #I want to have for example ds[1]$df, ds[1]$df2 with the respective > data.frames. > #How can I instantiate a list of data.frames pairs with different number of > rows? > > Thank you, > Rui > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Joshua Wiley Ph.D. Student, Health Psychology University of California, Los Angeles http://www.joshuawiley.com/ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.