Martin Spindler wrote:
> I have a matrix X which consists of 2 columns. I would like to convert this
> matrix into a list where every entry of the list consists of a single row of
> the matrix.
Here's another way besides split():
# returns a list of the matrix m's rows (rowcol=1) or columns
mat2lst <- function(m,rowcol=1) {
if (rowcol == 1) m <- t(m)
dm <- as.data.frame(m)
as.list(dm)
}
This seems to be faster than the split() approach for columns, but
slower for rows. Apparently the transpose operation makes the
difference. (You could try investigating via Rprof().)
Norm Matloff
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