Is this what you want?
sapply(sapply(strsplit(as.character(f1$keyword),' '),nchar),sum)

Weidong Gu

On Fri, Jun 10, 2011 at 1:25 PM, Jorge Ivan Velez
<jorgeivanve...@gmail.com> wrote:
> Hi Abraham,
>
> Try
>
> foo <- function(x){
> x <- as.character(x)
>  sapply(strsplit(x, " "), function(s) sum(nchar(s)))
> }
> foo(f1$keyword)
>
> HTH,
> Jorge
>
>
> On Fri, Jun 10, 2011 at 12:48 PM, Abraham Mathew <> wrote:
>
>> I'm trying to find the total number of letters in a row of a data frame.
>>
>> Let's say I have the following data frame.
>>
>> f1 <- data.frame(keyword=c("I live in Denver", I live in Kansas City, MO",
>> "Pizza is good"))
>>
>> The following function gives me the number of characters in each string.
>> So for "I live in Denver", I get 1, 4, 2, and 6. However, I want to know
>> the
>> total
>> number of characters (13).
>>
>> sapply(strsplit(as.character(f1$keyword), " "), nchar)
>>
>>
>> Thanks,
>> Abraham
>>
>>        [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

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