Brilliant!
> t1=matrix(1:15,5,3)
> t1
[,1] [,2] [,3]
[1,] 1 6 11
[2,] 2 7 12
[3,] 3 8 13
[4,] 4 9 14
[5,] 5 10 15
> t2=1:5
> t2
[1] 1 2 3 4 5
> sweep(t1, 1, t2)
[,1] [,2] [,3]
[1,] 0 5 10
[2,] 0 5 10
[3,] 0 5 10
[4,] 0 5 10
[5,] 0 5 10
> Date: Sun, 2 Mar 2008 14:56:22 -0300
> From: [EMAIL PROTECTED]
> To: [EMAIL PROTECTED]
> Subject: Re: [R] elegant way to minus on each row of a matrix
> CC: r-help@r-project.org
>
> Try this:
>
> sweep(mat, 1, vec)
>
>
> On 02/03/2008, Bo Zhou <[EMAIL PROTECTED]> wrote:
> >
> > How to do this in an elegant way formatrix/data frame/zoo?
> >
> > mat=
> > 1 2 3
> > 4 5 6
> > 7 8 9
> >
> > vector=
> > 1
> > 2
> > 3
> >
> >
> > result=
> > 0 1 2
> > 2 3 4
> > 4 5 6
> >
> > ie
> > 1-1 2-1 3-1
> > 4-2 5-2 6-2
> > 7-3 8-3 9-3
> >
> > Thanks in advance.
> >
> > _________________________________________________________________
> >
> >
> > 08
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
_________________________________________________________________
Need to know the score, the latest news, or you need your Hotmail®-get your
"fix".
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
