Dear R folks,
wanting to compare different implementations of a solution I want to
script it to iterate over the different implementations. Is there a way
to do this in the R shell/command line?
$ more /tmp/iterf.r
f1 <- function(n = 100000,
l = 100000)
{
z = n + l
}
f2 <- function(n = 100000,
l = 100000)
{
z = 2 * (n + l)
}
I tried the following, but it of course does not work.
> source("/tmp/iterf.r")
> print(f1(2,3))
[1] 5
> print(f2(2,3))
[1] 10
> for (i in 1:2) { print( fi(2, 3) ) }
Fehler in print(fi(2, 3)) : konnte Funktion "fi" nicht finden
Can I compose a command from values of variables?
Going on I tried to script that using the `r` from the package `littler`
[1]. Unfortunately because of the required quotes "" for the command
`source()` I am not able to expand the variable.
$ for i in $(seq 2); do r -e "print($i)" ; done
[1] 1
[1] 2
$ for i in $(seq 2); do r -e 'source("/tmp/iterf.r"); print(1)' ; done
[1] 1
[1] 1
$ # The next example does not work, because the variable $i does not
get expanded when surrounded by ''.
$ for i in $(seq 2); do r -e 'source("/tmp/iterf.r"); print(f$i(2, 3))'
; done
Fehler in print(f$i(2, 3)) : Objekt 'f' nicht gefunden
Ausführung angehalten
Fehler in print(f$i(2, 3)) : Objekt 'f' nicht gefunden
Ausführung angehalten
Searching for »iterating function names« with rseek.org did give any
good results. I also read the appendix in the introduction to R [2], but
this did not have anything regarding to this either.
Is there a way to script this?
Thanks,
Paul
[1] http://packages.debian.org/sid/littler
[2] http://cran.r-project.org/doc/manuals/R-intro.html#Scripting-with-R
f1 <- function(n = 100000,
l = 100000)
{
z = n + l
}
f2 <- function(n = 100000,
l = 100000)
{
z = 2 * (n + l)
}
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