See also ?tabulate. tabulate(x,8)
> Hi Paul, > > I would use something like this: > >> x <- c(2,2,3,3,4,6) >> table(x) > x > 2 3 4 6 > 2 2 1 1 >> x <- factor(x, levels=1:8) >> table(x) > x > 1 2 3 4 5 6 7 8 > 0 2 2 1 0 1 0 0 > > Sarah > > On Sun, Jul 31, 2011 at 5:41 PM, Paul Menzel > <paulepan...@users.sourceforge.net> wrote: >> Dear R folks, >> >> >> I am sorry to ask this simple question, but my search for the right >> way/command was unsuccessful. >> >> I have a vector >> >>> x <- c(2, 2, 3, 3, 4, 6) >> >> Now the values of x should be considered the index of another vector >> with possible greater length, say 8, and the value should be how often >> the indexes appeared in the original vector x. >> >>> length(result) >> [1] 8 >>> result >> [1] 0 2 2 1 0 1 0 0 >> >> >> Thank you in advance, >> >> Paul >> > > > > -- > Sarah Goslee > http://www.functionaldiversity.org > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
