Here's what you _should_ do
1) transpose
2a) as.data.frame
3a) fix the stupid default stringsAsFactor behavior
4a) convert the first 5 columns to numeric
dfrm <- as.data.frame( t( structure(.) ) )
dfrm[, 1:5] <-lapply(dfrm[, 1:5], as.character)
dfrm[, 1:5] <-lapply(dfrm[, 1:5], as.numeric)
Or:
1) transpose
2b) as.data.frame with stringsAsFactors= FALSE
3b) convert to numeric
On Aug 3, 2011, at 3:04 PM, Jeffrey Joh wrote:
I have a matrix that looks like this:
structure(c("0.0376673981759913", "0.111066500741386", "1", "1103",
"18", "OPEN", "DEPR", "0.0404073656092023", "0.115186044704599",
"1", "719", "18", "OPEN", "DEPR", "0.0665342096693433",
"0.197570061769498",
"1", "1103", "18", "OPEN", "DEPR", "0.119287147905722",
"0.356427096010845",
"1", "1103", "18", "OPEN", "DEPR"), .Dim = c(7L, 4L), .Dimnames =
list(
c("Sn", "SlnC", "housenum", "date", "hour", "flue",
"pressurization"
), c("10019.BLO", "1002.BLO", "10020.BLO", "10021.BLO")))
How do I convert rows 1-5 to numeric? I tried mode() <- "numeric"
but that doesn't change anything.
I also tried converting this to a table then converting to numeric,
but I got: (list) object cannot be coerced to type 'double'
Jeff
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David Winsemius, MD
West Hartford, CT
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and provide commented, minimal, self-contained, reproducible code.
