I don't know lme models very well, but if you have standard errors for your values, this shouldn't be too hard (as a last resort) using polygon()
For example x = 1:10 y = x^2 y.Err = 2*x y.Up = y + y.Err; y.Dn =y-y.Err # This graph is actually quite ugly so don't copy the formatting.... plot(x,y,type="n") polygon(c(x,rev(x)),c(y.Up,rev(y.Dn)),col="grey",border="red") # Use the rev commands so the border moves logically around the shaded area lines(x,y,type="b",lwd=3) # put the means back on top of the polygon Still, this is a little brute force and I'd imagine that someone else will shortly let you know how R can already do automatically. Michael Weylandt On Mon, Aug 8, 2011 at 1:07 PM, bjmjarrett <bjmjarr...@gmail.com> wrote: > Hi all, > > Im trying to plot confidence intervals for the fitted values I get with my > lme model in R. > > Is there any way I can plot this in the form of a shaded band, like the > output of geom_smooth() in ggplot2 package. ggplot2 seems to use only lm, > glm, gam, loess and rlm as smoothing methods. > > Any advice on the functions I should use to accomplish this will be very > helpful. > > Thank you very much. > > Ben > > -- > View this message in context: > http://r.789695.n4.nabble.com/confidence-interval-as-shaded-band-lme-tp3727645p3727645.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]]
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