Copying list one what was sent in reply. Anybody have a better solution?
On Aug 19, 2011, at 11:57 AM, Vasco Cadavez wrote:
Thanks,
A solution can be by substring to remove the /
then numeric will be ok! What you think?
How can I remove the /
with sub or gsub:
> sprintf("%010.0f", as.integer(gsub("/","",
c("4/3003","55/333","66/22")) ))
[1] "0000043003" "0000055333" "0000006622"
--
David.
Thanks
Vasco Cadavez
----- Menssagem Original -----
De:
"David Winsemius" <dwinsem...@comcast.net>
Para:
"David Winsemius" <dwinsem...@comcast.net>
Cópia:
"Vasco Cadavez" <vcadavez@ipbpt>, <r-help@r-project.org>
Enviado:
Fri, 19 Aug 2011 11:51:08 -0400
Assunto:
Re: [R] Leading zeros
On Aug 19, 2011, at 11:17 AM, David Winsemius wrote:
>
> On Aug 19, 2011, at 11:12 AM, Vasco Cadavez wrote:
>
>> Hello,
>> I have a dataset with an Id columns like:
>> 4/3003
>> 55/333
>> 66/22
>> I want to put leading zeros to get:
>> 00000004/3003
>> 000000055/333
>> 0000000066/22
>>
>> How can I solve this?
>
> ?sprintf
> ?formatC
>
I may have been too quick. Padding with leading zeros using sprintf
is
described for numeric but not for character types. There are severa
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