If you make your vector a data.frame, you will have row numbers accompanying your sorting
df<-data.frame(V1=c(1,4,3,2)) df$rows<-row.names(df) df[order(df$V1),] also, you shouldn't use c as a variable name since its an important R function... see your example :) Justin On Tue, Aug 23, 2011 at 4:59 PM, Chee Chen <chee.c...@yahoo.com> wrote: > Dear All, > I would like to know how to sort a vector of numeric values such that we > know the original index of each ordered component. Say, we have > c <- c(1,4,3,2) > csort <- sort(c,descreasing=FALSE) > With a few components of c, we can manually find out: > csort[1] = 1 = c[1], ie, the original index of csort[1] is 1, > csort[2] =2 =c[4], ie, the original index of csort[2] is 4. > > When length(c) is very large, manual checking is infeasible. > We can set up a for loop to compare and extract the index. However, is > there an easier way to do this, so that the output is the sorted vector and > their corresponding original indices. > Thanks > Chee > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
