On 10/1/2011 3:03 AM, jim holtman wrote:
try this:

vec1<- 
c(4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81)
vec2<- c 
(1,2,3,4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66)
vec3<- c (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,52)
  intersect(vec1,intersect(vec2, vec3))
  [1]  4  5  6  7  8  9 10 11 12 52


Or if your real problem may go to more vec's and you don't want to keep nesting the calls:

Reduce(intersect, list(vec1, vec2, vec3))
# [1]  4  5  6  7  8  9 10 11 12 52



On Sat, Oct 1, 2011 at 2:00 AM, Chris Conner<connerpha...@yahoo.com>  wrote:
Help-Rs,

I've got three vectors representing participants:

vec1<- 
c(4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81)
vec2<- c 
(1,2,3,4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66)
vec3<- c (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,52)

I'd like to return a vector that contains only the values that are shared 
across ALL THREE vectors. So the statement would return a vector that looked 
like this:
4,5,6,7,8,9,10,11,12,52

For some reason I initially thought that a cbind and a unique() would handle 
it, but then common sense sunk in.  I think the sleep deprivation is starting 
to take it's toll.  I've got to believe that there is a simple solution to this 
dilema.

Thanks in adance for any help!
C
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