Do you mean something like that? as.double(diff(c(ISOdatetime(2011,6,1,11,59,1.09),ISOdatetime(2011,6,5,11,59,1.09))),length=20) [1] 345600
________________________________ From: Jeff Newmiller <jdnew...@dcn.davis.ca.us> Cc: "R-help@r-project.org" <R-help@r-project.org> Sent: Monday, October 10, 2011 10:42 AM Subject: Re: [R] Handling Time in R Difftime doesn't "report" things. When you print it, it automatically selects an appropriate human-readable unit to display in, but that does not change its internal representation. If you must convert to seconds, you can do so using the as.double generic (as.double.difftime) with a units parameter. --------------------------------------------------------------------------- Jeff Newmiller The ..... ..... Go Live... DCN:<jdnew...@dcn.davis.ca.us> Basics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/Batteries O.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --------------------------------------------------------------------------- Sent from my phone. Please excuse my brevity. Thanks a lot. > >That helped. >One thing now is to have the difftime(y,x) to always report seconds. There are >times that there is a change in the day and thus the diff will report few days >difference. How can it always report only seconds? > >I would like to thank you in advance for your help > >B.R >Alex > > > >>________________________________ > >From: jim holtman <jholt...@gmail.com> > >Cc: "R-help@r-project.org" <R-help@r-project.org> >Sent: Friday, October 7, 2011 5:34 PM >Subject: Re: [R] Handling Time in R > >?ISOdatetime > > >> x <- ISOdatetime(2011,10,6,16,23,30.539) >> str(x) >POSIXct[1:1], format: "2011-10-06 16:23:30" >> y <- ISOdatetime(2011,10,6,16,23,30.939) >> difftime(y,x) >Time difference of 0.3999999 secs >> > > > >> Dear all, >> I would like to ask your help regarding handling time stamps in R. I think first I need a reference to read about their logic and how I should handle them. >> >> For example, this is a struct I have >> >> >> str(MyStruct$TimeStamps) >> �num [1:100, 1:6] 2011 2011 2011 2011 2011 ... >> >> MyStruct$TimeStamps[1,] >> [1] 2011.000�� 10.000��� 6.000�� 16.000�� 23.000�� >> 30.539 >> >> the last field contains seconds.milliseconds. >> >> How I can for example make calculations with time stamps like see if the >> MyStruct$TimeStamps[1,]-MyStruct$TimeStamps[2,] differ more than >> 300millisecond, or 3 days have passed? >> >> I would like to thank you in advance for your suggestions >> >> B.R >> Alex >> >> � � � �[[alternative HTML version deleted]] >> >> >> >________________________________ > >> R-help@r-project.org mailing list< br />> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> >> > > > >-- >Jim Holtman >Data Munger Guru > >What is the problem that you are trying to solve? >[[alternative HTML version deleted]] > >>________________________________ > >R-help@r-project.org mailing list >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
