Stefano Sofia wrote on 11/03/2011 11:28:08 AM:
>
> Dear R users,
> I have got the following data frame, called my_df:
>
> gender day_birth month_birth year_birth labour
> 1 F 22 10 2001 1
> 2 M 29 10 2001 2
> 3 M 1 11 2001 1
> 4 F 3 11 2001 1
> 5 M 3 11 2001 2
> 6 F 4 11 2001 1
> 7 F 4 11 2001 2
> 8 F 5 12 2001 2
> 9 M 22 14 2001 2
> 10 F 29 13 2001 2
> ...
>
> I need to count data in different ways:
>
> 1. count the births for each day (having 0 when necessary)
> independently from the value of the "labour" column
>
> 2. count the births for each day (having 0 when necessary), divided
> by the value of "labour" (which can have two valuers, 1 or 2)
>
> 3. count the births for each day of all the years (i.e. the 22nd of
> October of all the years present in the data frame) independently
> from the value of "labour"
>
> 4. count the births for each day of all the years (i.e. the 22nd of
> October of all the years present in the data frame), divided by the
> value of "labour"
>
> I tried with the command
>
> table(my_df$year_birth, my_df$month_birth, my_df$day_birth)
>
> which satisfies (partially) question numer 1 (I am not able to have
> 0 in the not available days).
>
> Is there a smart way to do that without invoking too many loops?
>
> thank you for your help
> Stefano Sofia
>
I'm having a hard time understanding what you're trying to calculate. Can
you show us what the results would look like from the example data you
shared?
Jean
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