Hello This is probably a basic question but I am quite new to R. I need to permute elements within rows of a binary matrix, such as
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,] 0 0 0 0 1 0 0 0 0 0 [2,] 0 0 1 1 0 0 0 1 1 0 [3,] 0 1 0 0 0 0 1 0 0 0 [4,] 0 0 0 0 0 0 1 1 0 0 [5,] 0 0 0 1 0 0 0 0 1 0 [6,] 0 0 1 1 0 0 0 0 0 1 [7,] 0 0 0 0 0 0 0 0 0 0 [8,] 1 1 0 1 0 0 0 1 0 1 [9,] 1 0 0 1 0 1 0 1 0 0 [10,] 0 0 0 0 0 0 0 1 0 1 That is, elements within each row are permuted freely and independently from the other rows. I see that is is workable by creating a array for each row, performing sample and binding the arrays again, but I wonder whether there is a more efficient way of doing the trick. Any help will be much appreciated. -- View this message in context: http://r.789695.n4.nabble.com/permutation-within-rows-of-a-matrix-tp4076989p4076989.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.