I worried it too, Do you have idear that what tools I can use?




ÔÚ 2011-11-21 00:13:26£¬"Uwe Ligges" <lig...@statistik.tu-dortmund.de> дµÀ£º
>
>
>On 20.11.2011 16:58, ÍÀ¾Ï´«Àñ wrote:
>> Thank you Ligges :)
>> one more question:
>> my response value "diagnostic" have 4 levels (0, 1, 2 and 3), so I use it 
>> like this:
>> "as.factor(diagnostic) ~ as.factor(7161521) +as.factor(2281517)"
>> Is it all right?
>
>
>Uhh. 4 levels? Than I doubt logistic regression is the right tool for 
>you. Please revisit the theory first: It is intended for 2 levels...
>
>
>Uwe Ligges
>
>
>
>
>
>>
>>
>>
>>
>> ÔÚ 2011-11-20 23:45:23£¬"Uwe Ligges"<lig...@statistik.tu-dortmund.de>  дµÀ£º
>>>
>>>
>>> On 20.11.2011 12:46, tujchl wrote:
>>>> HI
>>>>
>>>> I use glm in R to do logistic regression. and treat both response and
>>>> predictor as factor
>>>> In my first try:
>>>>
>>>> *******************************************************************************
>>>> Call:
>>>> glm(formula = as.factor(diagnostic) ~ as.factor(7161521) +
>>>> as.factor(2281517), family = binomial())
>>>>
>>>> Deviance Residuals:
>>>> Min 1Q Median 3Q Max
>>>> -1.5370 -1.0431 -0.9416 1.3065 1.4331
>>>>
>>>> Coefficients:
>>>> Estimate Std. Error z value Pr(>|z|)
>>>> (Intercept) -0.58363 0.27948 -2.088 0.0368 *
>>>> as.factor(7161521)2 1.39811 0.66618 2.099 0.0358 *
>>>> as.factor(7161521)3 0.28192 0.83255 0.339 0.7349
>>>> as.factor(2281517)2 -1.11284 0.63692 -1.747 0.0806 .
>>>> as.factor(2281517)3 -0.02286 0.80708 -0.028 0.9774
>>>> ---
>>>> Signif. codes: 0 ¡®***¡¯ 0.001 ¡®**¡¯ 0.01 ¡®*¡¯ 0.05 ¡®.¡¯ 0.1 ¡® ¡¯ 1
>>>>
>>>> (Dispersion parameter for binomial family taken to be 1)
>>>>
>>>> Null deviance: 678.55 on 498 degrees of freedom
>>>> Residual deviance: 671.20 on 494 degrees of freedom
>>>> AIC: 681.2
>>>>
>>>> Number of Fisher Scoring iterations: 4
>>>> *******************************************************************************
>>>>
>>>> And I remodel it and *want no intercept*:
>>>> *******************************************************************************
>>>> Call:
>>>> glm(formula = as.factor(diagnostic) ~ as.factor(2281517) +
>>>> as.factor(7161521) - 1, family = binomial())
>>>>
>>>> Deviance Residuals:
>>>> Min 1Q Median 3Q Max
>>>> -1.5370 -1.0431 -0.9416 1.3065 1.4331
>>>>
>>>> Coefficients:
>>>> Estimate Std. Error z value Pr(>|z|)
>>>> as.factor(2281517)1 -0.5836 0.2795 -2.088 0.0368 *
>>>> as.factor(2281517)2 -1.6965 0.6751 -2.513 0.0120 *
>>>> as.factor(2281517)3 -0.6065 0.8325 -0.728 0.4663
>>>> as.factor(7161521)2 1.3981 0.6662 2.099 0.0358 *
>>>> as.factor(7161521)3 0.2819 0.8325 0.339 0.7349
>>>> ---
>>>> Signif. codes: 0 ¡®***¡¯ 0.001 ¡®**¡¯ 0.01 ¡®*¡¯ 0.05 ¡®.¡¯ 0.1 ¡® ¡¯ 1
>>>>
>>>> (Dispersion parameter for binomial family taken to be 1)
>>>>
>>>> Null deviance: 691.76 on 499 degrees of freedom
>>>> Residual deviance: 671.20 on 494 degrees of freedom
>>>> AIC: 681.2
>>>>
>>>> Number of Fisher Scoring iterations: 4
>>>> *******************************************************************************
>>>>
>>>> *As show above in my second model it return no intercept but look this:
>>>> Model1:
>>>> (Intercept) -0.58363 0.27948 -2.088 0.0368 *
>>>> Model2:
>>>> as.factor(2281517)1 -0.5836 0.2795 -2.088 0.0368 **
>>>>
>>>> They are exactly the same. Could you please tell me what happen?
>>>
>>> Actually it does not make sense to estimate the model without an
>>> intercept unless you assume that it is exactly zero for the first levels
>>> of your factors. Think about the contrasts you are interested in. Looks
>>> like not the default?
>>>
>>> Uwe Ligges
>>>
>>>
>>>>
>>>> Thank you in advance
>>>>
>>>>
>>>> --
>>>> View this message in context: 
>>>> http://r.789695.n4.nabble.com/logistic-regression-by-glm-tp4088471p4088471.html
>>>> Sent from the R help mailing list archive at Nabble.com.
>>>>
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