On Nov 24, 2011, at 4:52 AM, Scott Tetrick wrote:
So I have a problem that I'm trying to get through, and I just can't
seem to get it to run very fast in R.
What I'm trying to do is to find in a vector a local peak, then the
next time that value is crossed later. I don't care about peaks
that may be lower than this first one - they can be ignored. I've
tried some sapply methods along the way, but they all are slower.
The best solution I have is a loop, and I just know there are smart
R folks that could help me eliminate it.
It looks as though you are reinventing hte function:
?cummax
Peak2Return <- function(v) {
Q <- (1:m)[diff(v)<0] ; find all the peaks
L <- Q[c(TRUE,v[Q[-1]] > v[Q[-length(Q)]])]
;
eliminate lower peaks
R <- sapply(L,function (x,v) { ((x+1):length(v))[v[x] < v[(x+1):m]]
[1]; }, v)
;
find the next crossing
out <- data.frame(peak=L,Return=R)
out
}
Thanks in advance!
David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.