You can try this also: sapply(DF[-match("AGE", names(DF))], plot, x=DF$AGE)
On 16/03/2008, Ing. Michal Kneifl, Ph.D. <[EMAIL PROTECTED]> wrote: > I have a problem I cannot get over for a long time. Imagine I have a > data frame with 17 colums. 16 of them are craniometric variables of > Cervus elaphus and one contains age. > The data frame has 83 rows. > I want to write a loop which plots the values of each craniometric > variable against the age. The names of columns are V1, V2, V3, etc... > What I have done till now was writing this: > > layout(matrix(1:16,4,4)) > plot(V1~AGE) > plot(V2~AGE) > . > . > . > . > etc. > How to assign a string in the loop so that the program understands it > is an object? > Thank for your help in advance. > > Michael > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.