Someone is bound to know a better way, but... subset(unlist(Version1_), subset=names(unlist(Version1_))=="First")
LCOG1 wrote > > Hi everyone, > I looked around the list for a while but couldn't find a solution to my > problem. I am storing some results to a simulation in a list and for each > element i have two separate vectors(is that what they are called, correct > my vocab if necessary). See below > > Version1_<-list() > for(i in 1:5){ > Version1_[[i]]<-list(First=rnorm(1),Second=rnorm(1)) > } > > What I want is to put all of the elements' 'First' vectors into a single > list to box plot. But whats a more elegant solution to the below? > > c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First) > > since i have 50 or more simulations this is impractical and sloppy. Do I > need to store my data differently or is their a solution on the back end? > Thanks all. > > Josh > -- View this message in context: http://r.789695.n4.nabble.com/Summarizing-elements-of-a-list-tp4142479p4142884.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.