On Dec 1, 2011, at 11:11 PM, Bert Gunter wrote:

strsplit is certainly an alternative, but your approach is
unnecessarily complicated and inefficient. Do this, instead:

sapply(strsplit(x,"/"),length)-1

Definitely more compact that the regex alternates I came up with, but one of these still might appeal in situations where it was desireable to have the source strings as labels:

> sapply( sapply(x$Col1, gregexpr, patt="/"), length)
    abc/def ghi/jkl/mno
          1           2

> nchar( sapply(x$Col1, gsub, patt="[^/]", rep="" ) )
    abc/def ghi/jkl/mno
          1           2

--
David


Cheers,
Bert

On Thu, Dec 1, 2011 at 7:44 PM, Florent D. <flo...@gmail.com> wrote:
Resending my code, not sure why the linebreaks got eaten:

x <- data.frame(Col1 = c("abc/def", "ghi/jkl/mno"), stringsAsFactors = FALSE) count.slashes <- function(string)sum(unlist(strsplit(string, NULL)) == "/")
within(x, Col2 <- vapply(Col1, count.slashes, 1))
        Col1 Col2
1     abc/def    1
2 ghi/jkl/mno    2


On Thu, Dec 1, 2011 at 10:32 PM, Florent D. <flo...@gmail.com> wrote:
I used within and vapply:

x <- data.frame(Col1 = c("abc/def", "ghi/jkl/mno"), stringsAsFactors = FALSE) count.slashes <- function(string)sum(unlist(strsplit(string, NULL)) ==
"/")within(x, Col2 <- vapply(Col1, count.slashes, 1))
         Col1 Col21     abc/def    12 ghi/jkl/mno    2

On Thu, Dec 1, 2011 at 1:05 PM, Bert Gunter <gunter.ber...@gene.com> wrote:
## It's not a data frame -- it's just a vector.

x
[1] "abc/def"     "ghi/jkl/mno"
gsub("[^/]","",x)
[1] "/"  "//"
nchar(gsub("[^/]","",x))
[1] 1 2


?gsub
?nchar

-- Bert

On Thu, Dec 1, 2011 at 8:32 AM, Douglas Esneault
<douglas.esnea...@mecglobal.com> wrote:
I am new to R but am experienced SAS user and I was hoping to get some help on counting the occurrences of a character within a string at a row level.

My dataframe, x,  is structured as below:

Col1
abc/def
ghi/jkl/mno

I found this code on the board but it counts all occurrences of "/" in the dataframe.

chr.pos <- which(unlist(strsplit(x,NULL))=='/')
chr.count <- length(chr.pos)
chr.count
[1] 3

I'd like to append a column, say cnt, that has the count of "/" for each row.

Can anyone point me in the right direction or offer some code to do this?

Thanks in advance for the help.

Doug Esneault






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--

Bert Gunter
Genentech Nonclinical Biostatistics

Internal Contact Info:
Phone: 467-7374
Website:
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______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.



--

Bert Gunter
Genentech Nonclinical Biostatistics

Internal Contact Info:
Phone: 467-7374
Website:
http://pharmadevelopment.roche.com/index/pdb/pdb-functional-groups/pdb-biostatistics/pdb-ncb-home.htm

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

David Winsemius, MD
West Hartford, CT

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