You've been given a workable solution already, but here's a one-liner: > x <- c('sta_+1+0_field2ndtry_0000$01.cfg' , > 'sta_+B+0_field2ndtry_0000$01.cfg' , 'sta_+1+0_field2ndtry_0000$01.cfg' , > 'sta_+9+0_field2ndtry_0000$01.cfg') > sapply(1:length(x), function(i)gsub("\\+(.*)\\+.", paste("\\+\\1\\+", i, > sep=""), x[i])) [1] "sta_+1+1_field2ndtry_0000$01.cfg" "sta_+B+2_field2ndtry_0000$01.cfg" [3] "sta_+1+3_field2ndtry_0000$01.cfg" "sta_+9+4_field2ndtry_0000$01.cfg"
Sarah, fan of regular expressions On Fri, Dec 2, 2011 at 6:30 AM, Alaios <ala...@yahoo.com> wrote: > Dear all, > I would like to search in a string for the second occurrence of a symbol and > replace the symbol after it > > For example my strings look like > > sta_+1+0_field2ndtry_0000$01.cfg > > I want to find the digit that comes after the second +, in that case is zero > and then over a loop create the strings below > > sta_+1+0_field2ndtry_0000$01.cfg > > sta_+1+1_field2ndtry_0000$01.cfg > > sta_+1+2_field2ndtry_0000$01.cfg > > sta_+1+3_field2ndtry_0000$01.cfg > > and so on.. > I have already tried strsplit but this will make things more complex... > > Could you please help me with that? > > B.R > Alex > -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.