On Dec 11, 2011, at 5:48 PM, Esteban Cervetto wrote:
2011/12/11 Esteban Cervetto <estebancs...@gmail.com>
I am working with uncensored data.
I have duration of workers compensation. Then I have for each the
number
of days thet it doesn't work.
This sample is not censored at right because I query only work
accidents
with date of return of work (saned)
That is because I have only one vector: the number of days that the
worker
doesn't work.
Reading works that uses this library, noticed that it need's a
vector to
mark the type of termination. That is because I did a formula Y(x)
= 1
as.numeric(T.**201110))~1
Your words were inspired me to do this: I solvet it putting to T.
201110
this proper vector and a vector of ones.
T.201110$censor <- apply(T.201110,1,function(row) 1) ##is
there a
best method to do that? it takes much time
I believe that this vector is superfluous, because the result of
the
formula is ever 1
You may be correct. The help page for Surv says "Although unusual, the
event indicator can be omitted, in which case all subjects are assumed
to have an event."
km1<-survfit(Surv(T.201110$dias,T.201110$censor)~1)
2011/12/10 David Winsemius <dwinsem...@comcast.net>
On Dec 10, 2011, at 6:39 PM, capitantyler wrote:
done it, again, i have the next problem
my traduction:
"The object (list) cannot be corced as "double"
Original:
*km1 <- survfit(Surv(as.numeric(T.**201110))~1)*
If you are adding the "**" for emphasis, it is certainly confusing my
understanding of what your original code was, which i'm now wondering
you ever provided. Perhaps it was the lack of a data argument. Hard to
tell.
This "works":
> fit <- survfit(Surv(time) ~ 1, data = aml[aml$status==1, ])
> plot(fit)
--
David
Error en Surv(as.numeric(T.201110)) :
el objeto (list) no puede ser coercionado a 'double'
I do not read that language, but I am surprised to see a single
vector
being used as an argument to Surv(). When I use Surv(. , .) it is
with two
vectors, an interval and a censor variable.
note that need it convert to numeric class, otherwise:
*km1 <- survfit(Surv((T.201110))~1)*
Error en Surv((T.201110)) : Time variable is not numeric
--
View this message in context: http://r.789695.n4.nabble.com/**
Kaplan-Meier-survfit-problem-**tp2015369p4181476.html<http://r.789695.n4.nabble.com/Kaplan-Meier-survfit-problem-tp2015369p4181476.html
>
Context? Yes. We do want context, but we don't want to go to no
steenking
Nabble.
Sent from the R help mailing list archive at Nabble.com.
Arrrgh. The rhelp mailing list is NOT at Nabble. Nabbel si a
commercial
mirror of the real thing. And it isn't really an archive. either,
since
they start discarding posts after a year or two.
--
David Winsemius, MD
West Hartford, CT
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.