On Dec 11, 2011, at 5:48 PM, Esteban Cervetto wrote:

2011/12/11 Esteban Cervetto <estebancs...@gmail.com>

I am working with uncensored data.

I have duration of workers compensation. Then I have for each the number
of days thet it doesn't work.
This sample is not censored at right because I query only work accidents
with date of return of work (saned)

That is because I have only one vector: the number of days that the worker
doesn't work.
Reading works that uses this library, noticed that it need's a vector to mark the type of termination. That is because I did a formula Y(x) = 1
as.numeric(T.**201110))~1

Your words were inspired me to do this: I solvet it putting to T. 201110
this proper vector and a vector of ones.


T.201110$censor <- apply(T.201110,1,function(row) 1) ##is there a
best method to do that? it takes much time

I believe that this vector is superfluous, because the result of the
formula is ever 1

You may be correct. The help page for Surv says "Although unusual, the event indicator can be omitted, in which case all subjects are assumed to have an event."




km1<-survfit(Surv(T.201110$dias,T.201110$censor)~1)




2011/12/10 David Winsemius <dwinsem...@comcast.net>


On Dec 10, 2011, at 6:39 PM, capitantyler wrote:

done it, again, i have the next problem

my traduction:
"The object (list) cannot be corced as "double"

Original:
*km1 <- survfit(Surv(as.numeric(T.**201110))~1)*

If you are adding the "**" for emphasis, it is certainly confusing my understanding of what your original code was, which i'm now wondering you ever provided. Perhaps it was the lack of a data argument. Hard to tell.

This "works":

> fit <- survfit(Surv(time) ~ 1, data = aml[aml$status==1, ])
> plot(fit)

--
David

Error en Surv(as.numeric(T.201110)) :
el objeto (list) no puede ser coercionado a 'double'


I do not read that language, but I am surprised to see a single vector being used as an argument to Surv(). When I use Surv(. , .) it is with two
vectors, an interval and a censor variable.



note that need it convert to numeric class, otherwise:

*km1 <- survfit(Surv((T.201110))~1)*
Error en Surv((T.201110)) : Time variable is not numeric
--
View this message in context: http://r.789695.n4.nabble.com/**
Kaplan-Meier-survfit-problem-**tp2015369p4181476.html<http://r.789695.n4.nabble.com/Kaplan-Meier-survfit-problem-tp2015369p4181476.html >


Context? Yes. We do want context, but we don't want to go to no steenking
Nabble.


Sent from the R help mailing list archive at Nabble.com.

Arrrgh. The rhelp mailing list is NOT at Nabble. Nabbel si a commercial
mirror of the real thing. And it isn't really an archive. either, since
they start discarding posts after a year or two.

--
David Winsemius, MD
West Hartford, CT




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David Winsemius, MD
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