Hi
>
> Dear R users,
>
> I am using the code below to generate a fitted value of b. I have about
> 300 different values for for y (y1, y2, ...y300) which means I will have
> to write the code below 300 times to generate the 300 different fitted
> values for y. Is there a short way of doing that ?
With lm you can use several dependent variables to get result, but I do
not know if it works with gam.
You can put y1 - y300 to list and than use lapply or for cycle to do the
analysis and store results in a list (list.y).
something like (untested)
for (i in 1:300) {
b[i] <- gam(list.y[i]~s(x1,x2, k=100, data=dat)
}
Regards
Petr
>
> Many thanks in advance
> Mintewab
>
> library(mgcv)
> dat <- read.table("e:/minti's laptop/C/GBG/allround_survey/
> rainfallGPS.csv", header=T, sep=",")
> b<-gam(y1~s(x1, x2, k=100),data=dat)
> vis.gam(b)
> fitted(b)
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