Thank you all for your help and best wishes for the holiday season.
Matt Considine
On 12/24/2011 8:38 AM, William Revelle wrote:
Dear Matt, Sarah and Rui,
To answer the original question for creating a symmetric matrix
v<-c(0.33740, 0.26657, 0.23388, 0.23122, 0.21476, 0.20829, 0.20486,
0.19439, 0.19237,
0.18633, 0.17298, 0.17174, 0.16822, 0.16480, 0.15027)
z<-diag(6)
z[row(z)> col(z)]<- v
z<- z + t(z)
diag(z)<- 0
z
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 0.00000 0.33740 0.26657 0.23388 0.23122 0.21476
[2,] 0.33740 0.00000 0.20829 0.20486 0.19439 0.19237
[3,] 0.26657 0.20829 0.00000 0.18633 0.17298 0.17174
[4,] 0.23388 0.20486 0.18633 0.00000 0.16822 0.16480
[5,] 0.23122 0.19439 0.17298 0.16822 0.00000 0.15027
[6,] 0.21476 0.19237 0.17174 0.16480 0.15027 0.00000
Bill
On Dec 24, 2011, at 6:04 AM, Sarah Goslee wrote:
Or the slightly shorter:
z<-diag(6)
z[row(z)> col(z)]<- v
which is what lower.tri() does,
and
z<- diag(6)
z[lower.tri(z)]<- v
also works.
Sarah
On Fri, Dec 23, 2011 at 9:31 PM, Rui Barradas<ruipbarra...@sapo.pt> wrote:
Matt Considine wrote
Hi,
I am trying to work with the output of the MINE analysis routine found at
http://www.exploredata.net
Specifically, I am trying to read the results into a matrix (ideally an
n x n x 6 matrix, but I'll settle right now for getting one column into
a matrix.)
The problem I have is not knowing how to take what amounts to being one
half of a symmetric matrix - excluding the diagonal - and getting it
into a matrix. I have tried using "lower.tri" as found here
https://stat.ethz.ch/pipermail/r-help/2008-September/174516.html
but it appears to only partially fill in the matrix. My code and an
example of the output is below. Can anyone point me to an example that
shows how to create a matrix with this sort of input?
Thank you in advance,
Matt
#v<-newx[,3]
#or, for the sake of this example
v<-c(0.33740, 0.26657, 0.23388, 0.23122, 0.21476, 0.20829, 0.20486,
0.19439, 0.19237,
0.18633, 0.17298, 0.17174, 0.16822, 0.16480, 0.15027)
z<-diag(6)
ind<- lower.tri(z)
z[ind]<- t(v)[ind]
z
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 1.00000 0.00000 0 0 0 0
[2,] 0.26657 1.00000 0 0 0 0
[3,] 0.23388 0.19237 1 0 0 0
[4,] 0.23122 0.18633 NA 1 0 0
[5,] 0.21476 0.17298 NA NA 1 0
[6,] 0.20829 0.17174 NA NA NA 1
Hello,
Aren't you complicating?
In the last line of your code, why use 'v[ind]' if 'ind' indexes the matrix,
not the vector?
z<-diag(6)
ind<- lower.tri(z)
z[ind]<- v #This works
z
Rui Barradas
--
Sarah Goslee
http://www.functionaldiversity.org
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