> > findInterval(6.2, sort(x)) > [1] 704 > > xecdf <- ecdf(x) > > xecdf(6.2) > [1] 0.704
thanks, that helped a lot! On 11.01.2012, at 14:58, David Winsemius wrote: > > On Jan 11, 2012, at 8:12 AM, Martin Batholdy wrote: > >> Hi, >> >> I have a vector with values: >> >> x <- rnorm(1000, 5, 2) >> >> >> and one single value: >> y <- 6.2 >> >> now I would like to know the percent rank of y based on the >> 'population'-vector x. >> Is there a convenient function that calculates the percent rank of a y for >> the given vector x? > > Two options : > 1) sort x and use findInterval, divide the index by length(x) and multiply by > 100 > (It can all be done as a one-liner.) > > 2) I generally "reach for" the `ecdf` "function making machine" when I see > sample quantile problems and see if I can cast the problem in terms for which > it applies. > > For my random draw I get: > > findInterval(6.2, sort(x)) > [1] 704 > > xecdf <- ecdf(x) > > xecdf(6.2) > [1] 0.704 > > -- > David Winsemius, MD > West Hartford, CT > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
