On Wed, Jan 25, 2012 at 09:10:13AM -0800, yan wrote: > thanks petr, > what if I got 200 elements, so I have to write expand.grid(x1=1, x2=1:2, > x3=1:3, x4=1:3, x5=1:3....x200=1:3))?
Hi. As others told you, the problem is not in reformulating the command in a concise way, but in enormous memory and time requirements of constructing all these partitionings. Try to formulate further conditions, which the required partitionings should satisfy. This can reduce their number or allow a different approach to solve your problem than listing all partitionings. Petr Savicky. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
