On Feb 6, 2012, at 5:26 PM, Francis Keyes wrote:
Hi David,
I have 2 tables, each with several columns and rows of data. I am
only interested in the data from column 6, which contains values in
the range -PI to PI. I want to plot the data from tableD with the y
axis denoting percentage with respect to tableR. So if data points in
the break 2 - 3 appear half as often in tableD as in tableR, the y
axis should show 50 percent. Does that make sense?
I've been plotting the data like this to date:
hist(tableD[,6],ylab="frequency", xlab="angle")
It all makes sense, (and it made sense before) , but your
responsibility is to provide data.
(Contrats on plain text lesson successfully met.)
Thanks a lot for your help
On Mon, Feb 6, 2012 at 1:31 PM, David Winsemius <dwinsem...@comcast.net
> wrote:
On Feb 6, 2012, at 12:23 PM, Francis Keyes wrote:
Thanks. How do you suggest I use the reference population?
Sorry, I'm new to R and just don't see it. If i can get a plot
that is counts or density relative to my reference data it would
be ideal.
It is difficult to specify "how" when we have no "what". The "what"
is your responsibility, not ours. My thought was to use the ratio
of the results of hist() on the two populations which would then
be offered back to hist or barplot. ....which (of course) requires
that the 'breaks' be the same. Provide an example of your R
representations of the reference population and tested population
and all will become clear.
(And learn to post in plain text, please.)
--
David Winsemius, MD
West Hartford, CT
On Mon, Feb 6, 2012 at 1:12 AM, David Winsemius <dwinsem...@comcast.net
> wrote:
On Feb 5, 2012, at 8:31 PM, Francis Keyes wrote:
With R and the hist function, is there a way to make a histogram
in which
the y axis denotes propotion with respect to a separate sample
dataset of
the same range instead of frequency?
hist() returns an object with both "counts" and "density". If you
had a reference population it should be a fairly simple matter to
use one or the other of those.
David Winsemius, MD
West Hartford, CT
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