Thanks everyone for your help the qt function worked like a dream. I ended up using it like this; T <- qt((1-0.05/2),7) to estimate 95% intervals divided by 2. 7 would be the number of days sampled.I got the same result I get with Systat.
> > I can't actually tell which function in R is the > > equivalent to TINV function in Excel. > > Anyone familiar with that function? Thanks > > TINV is returns a half range t quantile function and > it returns 0 from 1 > and 5 million from 0; =TINV(0.1,100) produces > 1.6602348, so I think you > need to divide your arguments by 2 and subtract that > from 1 to get the > same result with qt() > > > qt(.95,100) > [1] 1.660234 > > qt(.5,100) > [1] 0 > > -- > David Winsemius > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > Felipe D. Carrillo Fishery Biologist Department of the Interior US Fish & Wildlife Service California, USA ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
