Valerie,
In additio to Sarah's suggestion, you could also use
rowSums(c5[, 2:4] > 0)
HTH,
Jorge.-
On Tue, Feb 21, 2012 at 7:45 PM, Sarah Goslee <> wrote:
> There's almost always a better way than a loop (although
> sometimes it isn't worth the effort to figure it out). This time
> it's straightforward:
>
> > apply(c5[, 2:4], 1, function(x)sum(x > 0))
> [1] 3 2 1 0 3
>
> Sarah
>
> On Tue, Feb 21, 2012 at 6:04 PM, Valerie Moore <> wrote:
> > Hi,
> >
> > Is there a short way of doing this?
> >
> > I have the following table in R:
> >
> > 12.0 0.5 0.6 0.2 0 0
> >
> > 12.3 1.2 0.8 0 0 0
> >
> > 13.1 0 1.2 0 0 0
> >
> > 10.1 0 0 0 1.3 0
> >
> > 10.2 1.3 1.2 0.9 0 1.3
> >
> >
> > So I have 5 rows and 6 columns. For each row, I want to count the number
> of times that the value is greater than 1 (FOR COLUMNS 2 TO 4).
> > I have the following R code.
> >
> > count=numeric()
> > for (i in 1:5) {
> > count[i]=sum(c5[i,2:4]>0)
> > }
> >
> > The result is
> >> count
> > [1] 3 2 1 0 3
> >
> > Is there a short way of doing this (instead of doing the loop)?
> >
> > Thank you.
> >
> >
> > -Valerie
>
> --
> Sarah Goslee
> http://www.functionaldiversity.org
>
> ______________________________________________
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