My apologies. The last line should have been
with(d, sort(c(as.character(x1), as.character(x2))))
Regards,
Jorge.-
On Sat, Feb 25, 2012 at 2:03 AM, Jorge I Velez <> wrote:
> Perhaps the following?
>
> d <- structure(list(x1 = structure(1:4, .Label = c("a", "c", "e",
> "g"), class = "factor"), x2 = structure(1:4, .Label = c("b",
> "d", "f", "h"), class = "factor")), .Names = c("x1", "x2"), class =
> "data.frame", row.names = c("1",
> "2", "3", "4"))
>
> with(d, c(as.character(x1), as.character(x2)))
> # [1] "a" "c" "e" "g" "b" "d" "f" "h"
>
> HTH,
> Jorge.-
>
>
> On Fri, Feb 24, 2012 at 5:32 PM, thomas88 <> wrote:
>
>> Hello,
>> I am looking for a way to transform an array into a list (or a string).
>> My array has two columns 1 and 2, and I would like to create a list of the
>> values.
>>
>> Let's say I have :
>>
>> x1 x2
>> 1 a b
>> 2 c d
>> 3 e f
>> 4 g h
>>
>> What I would like to obtain is a,b,c,d,e,f,g,h.
>>
>> I tried without success melt and reshape ( reshape(my_array,
>> direction="long", varying=1:2) ) but I cannot get it work.
>>
>> Thanks a lot !!!
>> thomas
>>
>> --
>> View this message in context:
>> http://r.789695.n4.nabble.com/Table-into-a-list-tp4418804p4418804.html
>> Sent from the R help mailing list archive at Nabble.com.
>>
>> ______________________________________________
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>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
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