Le jeudi 12 avril 2012 à 12:29 +0300, Tal Galili a écrit :
> Hi David,
> You bring up a good question. I am not sure what is the "right" way to
> solve it. But here is a simple solution I put together:
>
> x = c(1:10,5)
> y = x
> x[c(2,3)] <- NA
>
> # reproducing the problem:
> y[x==5]
>
> na2F <- function(x) {
> x2 <- x
> x2[is.na(x)] <- F
> x2
> }
> na2F(x==5)
>
> # "solved"
> y[na2F(x==5)]
>
>
> I'd be happy to see other solutions to it.
You can simply use the built-in function which() for this, since it
removes NAs, only returning the position of TRUE elements:
which(c(NA, 1:10 == 5))
[1] 6
My two cents
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
