Yes this what I meant. I think no need for this line h=listfile[[n]],if I
can just put it directly in the other line to do the calculations for every
file in my list.they are not really elements.they are files.
what I need is just this:get the size of each file in my list then
/67420/4,to get the number of rows and assign that to b . so now b will be
used later as a loop.
I tried this also:
for (n in 1:length(listfile)).{
h=listfile[[n]]
b=file.info(h[[n]])$size/67420/4
}
then I got this :Error in h[[n]] : subscript out of bounds
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