On 04/28/2012 02:32 PM, Jim Lemon [via R] wrote:
> On 04/28/2012 04:12 AM, bodiless wrote:
>
> > Dear R-users
> >
> > I hope someone could help me on this problem.
> >
> > I want to create a multiple kiteChart showing the real values with a
> > scalebar on each indicating the scale .
> > Here are some sample data to show what I want to achieve.
> >
> > Y<- read.table(textConnection("Sample1 Sample2
> > 60 20
> > 150 50
> > 300 100"),header=TRUE)
> > X<- read.table(textConnection("Sample1 Sample2
> > 6 2
> > 15 5
> > 30 10"),header=TRUE)
> > par(las=1,mfrow=c(2,1))
> > kiteChart(t(Y),xlim=c(-400,400),timelabels=c("2-3cm","1-2cm","0-1cm"),
> > normalize=FALSE,shownorm=FALSE,timex=FALSE)
> > kiteChart(t(X),xlim=c(-400,400),timelabels=c("2-3cm","1-2cm","0-1cm"),
> > normalize=FALSE,shownorm=FALSE,timex=FALSE)
> >
> > My first problem with the above approach is that the kites in both
> graphs
> > are overlapping. If I take out the xlim switch then the kites are too
> large
> > and you can't see anything. If I use the xlim switch then they are not
> > plotted next to each other as they should. Please note that I could use
> > normalize=TRUE and then they are plotted ok but I don't want to
> normalize
> > them.
> >
> > My second problem is that I have data which are way too smaller that the
> > values shown in data.frame X. So, if the first graph has large values
> and
> > the second very small values then on the second graph you see only a
> thin
> > line. Therefore I want to multiply the small values of data.frame X by a
> > factor to make the kites visible but then I need to place a scalebar
> on each
> > graph showing e.g. that for the 0-1cm the top graph is 0-300 and the
> lower
> > graph is 0-30.
> >
> Hi bodiless,
> You have just contributed to the development of kiteChart. I have
> inserted another argument (varpos) that allows the user to place the
> "kiteline" along the axis orthogonal to the "time" axis. With the
> following code, I think you will get what you want.
>
> kiteChart(t(Y),xlim=c(-400,400),
> timelabels=c("2-3cm","1-2cm","0-1cm"),
> normalize=FALSE,shownorm=FALSE,timex=FALSE,
> varpos=c(-100,300))
> axis(3,at=c(-400,-100,200,300,400),labels=c(-300,0,300,0,100))
>
>
> The last line puts axis tick labels on the top of the plot, which is
> what I think you want. The revised function is attached, let me know if
> any other mods are needed. The revised function will appear shortly in a
> new version.
>
> Jim
>
Hi Jim,
Fantastic! I would never thought that my message would create such a
great and immediate respond.
With your new "varpos" function and the code you suggested I managed to
make the kites look exactly the way I want. I wonder however, if you
could add some automation to this function.
Have a look at the new data below and the kite charts which are created
after using your code:
Y<- read.table(textConnection("Sample1 Sample2
60 20
150 50
300 300"),header=TRUE)
X<- read.table(textConnection("Sample1 Sample2
6 2
15 5
30 7"),header=TRUE)
par(las=1,mfrow=c(2,1))
kiteChart(t(Y),xlim=c(-650,650),
timelabels=c("2-3cm","1-2cm","0-1cm"),
normalize=FALSE,shownorm=FALSE,timex=FALSE,
varpos=c(-350,350))
axis(3,at=c(-650,-350,-50,50,350,650),labels=c(0,"",300,0,"",150))
kiteChart(t(X),xlim=c(-65,65),
timelabels=c("2-3cm","1-2cm","0-1cm"),
normalize=FALSE,shownorm=FALSE,timex=FALSE,
varpos=c(-35,35))
axis(3,at=c(-65,-35,-5,28,35,42),labels=c(0,"",30,0,"",7))
Now, look at the top kite. In order to find the values for the xlim
switch one needs to do the following calculations manually: first find
the largest value from data.frame.Y, (300), then double this value (600)
and then add a small space, say 50, so that the two variables are not
touching each other (otherwise the 300 of variable 1 and the 0 of
variable 2 would overlap).
Similarly, for the varpos switch, one needs to find the two centers of
the xlim=c(-650,650) space to find varpos=c(-350,350).
Finally, for the axis tick marks (for example see Sample 2 at the bottom
kite) one has to find the max value of Sample 2 in data.frame.X (7) and
then add and subtract this value from its varpos value (35) to find the
correct positions of the tick marks (28,35,42).
As you can imagine, this is not a big problem with two variables in a
KiteChart but it could get frustrating if one has more than two variables.
But maybe I am asking too much.
Anyway, thanks again for your great work and help.
Nikos
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