See ?sparseMatrix from package Matrix. Eloi
On 12-05-07 02:23 PM, Lucas wrote: > Dear R people. > I´m facing a big problem. > I need to create a matrix with 10.000 columns and 750.000 rows. > matrix<- as.data.frame(matrix(data=0L, nrow=750000, ncol=10000) > as you can see, the data frame has huge dimesions. I was able to find out > about thr "L" in data, this way I´m telling that my data is "integer" > class. By doing this > object.size(matrix) tells me that this is half of the matrix when I don´t > define as integer (L) > The data that I´ll be filling with my matrix will be 0 and 1, nothing else, > so I could use less bytes. > so, my cuestion is, How can I create the same matrix but using even less > bytes? > > I´ll appreciate if you can help me. > > Thank you. > Lucas > > [[alternative HTML version deleted]] > > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Eloi Mercier Bioinformatics PhD Student, UBC Paul Pavlidis Lab 2185 East Mall University of British Columbia Vancouver BC V6T1Z4 [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
