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On 25/05/12 11:45, Minerva Mora wrote:
Hi, I apologize for my english. I´m trying to read a file, but the name of this file changes every day, for example: today is May 24, 2012 bonos<- read.table("C:/Bonos/*20120524*.csv", header=TRUE, sep="\t") So, tomorrow I want to read the file again, but i don´t want to put the date by myself, i want this automatically. I know that if a put day() this instruccion gives me the date. My problem is, I don´t know how to concatenate these: -"C:/Bonos/ -the date -.csv" I tried this: bonos<- read.table(cat(cit,dia,extension), header=TRUE, sep="\t") where --cit is *"\"C:/Bonos/"* --dia is *dia<-format(today, "%Y%m%d")* --extension is *extension<-".csv\""* but i have this problem: "C:/Bonos/ 20120524 .csv"*Error in read.table(cat(cit, dia, extension), header = TRUE, sep = "\t") : * * 'file' must be a character string or connection* What can i do? Thanks! -- View this message in context: http://r.789695.n4.nabble.com/How-to-open-a-file-with-a-name-changed-tp4631261.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.