On 05.06.2012 00:36, Erdal Karaca wrote:
Thanks all, that worked!

Yes, it should be
for (i in 1:length(a)) a[i]<- scalar * a[i] * i

And now is...

a<- a * scalar * seq_along(a)

That is almost as cool as the PERL programming language :-)


Almost?

Uwe Ligges



2012/6/4 Rui Barradas<ruipbarra...@sapo.pt>

Hello,

Just learning the alphabet? If yes, there's a difference between 'v' and
'a'.

Now more seriously. Your description and your loop don't do the same.

Description:
vm<- scalar * v * seq_along(v)

Loop:
a<- scalar * a

Also, seq_along is the way to do it, it works even if length(a) == 0.

Hope this helps,

Rui Barradas

Em 04-06-2012 21:25, Erdal Karaca escreveu:

(Just learning R)

I have this vector:

v<- c(1:10)

Now, I want to multiply each element of that vector with a scalar value
multiplied with its index:

vm<- v * scalar * indexOfCurrentElementOf_v

Is that possible without using a loop?

In a loop I would do this:

for (i in 1:length(a)) a[i]<- scalar * a[i]

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