It's working!!!! I am excited than ever!!
Thank you so much!!!!

On Wed, Jun 27, 2012 at 12:45 PM, Dimitris Rizopoulos <
d.rizopou...@erasmusmc.nl> wrote:

> you will have to check what function pargev() returns as a result. I would
> guess that is probably a list. In any case, you could use something like
> the following:
>
> estIID50 <- lapply(IID50, function (m)  pargev(lmom.ub(m)))
>
> I hope it helps.
>
> Best,
> Dimitris
>
>
>
> On 6/27/2012 1:31 PM, Al Ehan wrote:
>
>> Hi R-users,
>>
>> I'm trying to repeat the same procedure to 1000 data set. I know this is
>> very easy, but I got stuck finding the right and fastest way in running
>> it.
>>
>> IID50=Riidf[1:50,1:1000] #where IID50 is a dataframe consist of 1000 time
>> series(as column) and 50 time scales (row).
>>
>> #what I tried to do:
>>
>> estIID50=rep(NA,1000)
>> for (i in 1:1000)
>> estIID50[i]=pargev(lmom.ub(**IID50[1:50,i]))
>>
>> #warning message
>>  In estIID50[i] = pargev(lmom.ub(IID50[1:50, i])) :
>>   number of items to replace is not a multiple of replacement length
>>
>> #pargev is a function from lmomco package. I would like to apply it to the
>> 1000 set of time series that I have in the IID50, without having to do it
>> manually.
>> #I dont understand what is the warning warns about
>>
>> Can somebody help me?
>>
>>        [[alternative HTML version deleted]]
>>
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>> PLEASE do read the posting guide http://www.R-project.org/**
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>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
> --
> Dimitris Rizopoulos
> Assistant Professor
> Department of Biostatistics
> Erasmus University Medical Center
>
> Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
> Tel: +31/(0)10/7043478
> Fax: +31/(0)10/7043014
> Web: 
> http://www.erasmusmc.nl/**biostatistiek/<http://www.erasmusmc.nl/biostatistiek/>
>
>
>

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