On Jun 28, 2012, at 5:03 PM, arun.gurubaramurugeshan wrote:
I am creating a nested for loop and following are the codes I'm
using, but I
am not acheiving what I want.
I have a vector
d<-151:159
I have another vector
e<-e<-c("apple", "orange", "banana")
I need to create f as
151apple
151orange
151banana
.
.
159apple
159orange
159banana
I admit that I think Bert's solution is way kewler than mine, but I
would not have thought of using interaction() to mimic the "crossed"
use of rep()
paste(as.character(rep(d, each=length(e))), rep(e, times=length(d) ),
sep="")
(Looking at the code for interaction one sees that this is how it was
coded.)
The other R functions to remember for this sort of loop-avoidance are
'outer' and 'expand.grid'.
> outer(d,e,paste, sep="")
[,1] [,2] [,3]
[1,] "151apple" "151orange" "151banana"
[2,] "152apple" "152orange" "152banana"
[3,] "153apple" "153orange" "153banana"
[4,] "154apple" "154orange" "154banana"
[5,] "155apple" "155orange" "155banana"
as.vector( outer(d, e, paste, sep="") )
--
David.
Here is how I wrote nested for loop...
for (i in 1:length(d))
{ for (j in 1:length(e))
{
x[j]<-paste(d[i],e[j],sep="")
print(x[j])
}
}
The result of the above codes is....
for (i in 1:length(d))
+ { for (j in 1:length(e))
+ {
+ x[j]<-paste(d[i],e[j],sep="")
+ print(x[j])
+ }
+ }
[1] "151apple"
[1] "151orange"
[1] "151banana"
What do I need to do this looping produce the desired result.
Thanks
Arun
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